Note: Reader software still needs to be installed. Plus easy-to-understand solutions written by experts for thousands of other textbooks. You can cancel at any time. Problem solving and mathematical modeling are introduced early and reinforced throughout, providing students with a solid foundation in the principles of mathematical thinking. The slope of a vertical line is undefined. So the slope is So 0 and the y-intercept is 4.
So the So the slope slope is undefined, and there is no y-intercept. This is a. To determine if the lines are parallel or perpendicular, we find their slopes. We first plot the points to find the pairs of points that determine each side. The slope of AD is.
Since these slope are equal, these two sides are parallel. We first plot the points to determine the perpendicular sides. Next find the slopes of the sides. The slope of AB is. So the sides form a rectangle. We find the intercepts the length of the sides. The slope of the line that contains them is. The y-intercept is the number of spaces at the flea market, , and the x-intercept is the cost per space when the.
So the linear The V -intercept represents the cost of the computer. The y-intercept represents the pressure at the surface. The temperature is increasing at a constant rate when the slope is positive, decreasing at a constant rate when the slope is negative, and constant when the slope is 0.
We label the three points A, B, and C. If the sum of the two smaller distances equals the largest distance, the points A, B, and C are collinear. Another method: Find an equation for the line through A and B. Then check if C satisfies the equation. If so, the points are collinear. There are many possibilities. So Since the Since D is positive, this equation has two real solutions.
Since D is negative, this equation has no real solution. We want to find the values of k that make the discriminant 0. In either case, the two numbers are 19 and Let n be one even number. Thus the width is 25 feet and the length is 35 feet. Since area is length times width, we have. Since the width must be positive, the width is 12 feet. We use the perimeter to express the length l of the garden in terms of width. So the length is 60 feet and the width is 40 feet.
Region A has dimensions 14 in. The shaded area is the sum of the area of a rectangle and the area of a triangle. Let x be the length of one side of the cardboard, so we start with a piece of cardboard x by x. Let r be the radius of the can. Using the Pythagorean Theorem, we have. Thus the width is feet and the length is feet. Let h be the height of the flagpole, in feet. Since the distance between the points where the wires are fixed to the ground is equal to one guy wire, the triangle is equilateral, and the flagpole is the perpendicular bisector of the base.
The first choice seems more likely! Let r be the speed of the southbound boat. Therefore, the ball reaches 24 feet in 1 second ascending and again after 1 12 seconds descending.
So the greatest height reached by the ball is 25 feet. Thus the ball reaches the highest point of its path after 1 14 seconds. So the ball hits the ground in 2 12 s. To find. Thus the fish population will again be the same 17 years later, that is, on January 1, Since ft is too wide, the width of the lawn is 30 ft, and the factory is ft by ft. Let h be the height the ladder reaches in feet.
Let t be the time, in hours it takes Irene to wash all the windows. Let t be the time, in hours, it takes Kay to deliver all the flyers alone. Let x be the distance from the center of the earth to the dead spot in thousands of miles.
Using the Quadratic Formula, we obtain. Let x equal the original length of the reed in cubits. The width is 30x.
Since x must be positive, the original length of the reed is 6 cubits. Since both solutions are imaginary, In these cases, inadmissible solutions are identified later in the. You can verify that these are both solutions to the original equation.
Thus, the two real solutions are 0 and 1. Thus, the two real solutions are 0 and 2. The solutions are 0 and 3 3. The solutions are 0 We must check the original equation to make sure this value of z does not result in a zero denominator. This is indeed a solution to the original equation.
We verify that these are both solutions to the original equation. We verify that both are solutions to the original equation. Since the radicand is negative, there is no real solution. Both are admissible, so the solutions are. These are only potential solutions since squaring is not a reversible operation. We must check each potential solution in the original equation. We verify that this is a solution to the original equation.
This equation has no real solution. The only solution is We choose the exponent 16 because the LCD of 2, 3, and 6 is 6. The solutions are and The solutions are 9 and 4. Squaring both sides again, we The solutions are 0 and 2. By definition of u we require it to be nonnegative. Squaring both sides again, we get. After 5 people Let x be the number of people originally intended to take the trip. Since the number of people on the trip must be positive, originally 50 people intended to take the trip.
Since n must be positive, there are now 4 friends in the group. So it will take 89 days for the fish population to reach PB Acceptable. HC Good. HC VeryGood. Satisfaction Guaranteed! James Stewart Pre-Owned. Please share with your friends, let's read it!!
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